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Verified Answer :

AgNO3(aq)
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Answer:

The correct answer is silver nitrate solution that is \(AgNO_3(aq)\).

Explanation:

To separate \(Br^-\) from \(NO_{3}^-\) ions we will use silver nitrate solution. On addition of silver nitrate solution in a mixture of bromide and nitrate ions.

The silver ion will react with bromide ions to form silver bromide which will get precipitated out as yellow color solid from a mixture.

\(AgNO_3(aq)+Br^-(aq)\rightarrow AgBr(s)+NO_{3}^-(aq)\)

\(AgNO_3(aq)+NO_{3}^-(aq)\rightarrow\) no reaction