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Considering ideal gas behavior, the volume of 1 mol of gas at STP is 22.4 L; then the volume occupied by 1.9 moles is 1.9mol*22.4L/mol = 42. 6 L.

Answer: 43 L

Answer : The volume of chlorine gas is, 42.56 L

Solution : Given,

Moles of chlorine gas = 1.9 moles

As we know that,

At STP, 1 mole contains 22.4 L volume of gas

As, 1 mole of chlorine gas contains 22.4 L volume of chlorine gas

So, 1.9 moles of chlorine gas contains \(22.4\times 1.9=42.56L\) volume of chlorine gas

Therefore, the volume of chlorine gas is, 42.56 L