Which is the equation of the line with slope 3 that contains point (-1, 5)?

y _ 5 = 3(x + 1)

y _ 1 = 3(x + 5)

y _ 1 = 3(x _ 5)

y _ 5 = 3(x - 1)

The expression above is in a point-slope form which is:

y-y1 = m(x-x1)

Therefore, from the given problem:

m = 3
y1 = 5
x1 = -1

The transformed equation would be:

y-5 = 3(x+1) which is the first choice.

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Which is the equation of the line with slope 3 that contains point (-1, 5)?y _ 5 = 3(x + 1) y _ 1 = 3(x + 5) y _ 1 = 3(x _ 5) y _ 5 = 3(x - 1)

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Related Questions

Which is the equation of the line with slope 3 that contains point (-1, 5)?

y _ 5 = 3(x + 1)

y _ 1 = 3(x + 5)

y _ 1 = 3(x _ 5)

y _ 5 = 3(x - 1)