What part of the coordinate plane is equidistant from the points a(-3,2) and b(3,2)?
We first find the midpoint of the points:
Midpoint: ((3-3)/2 , (2 + 2)/2)
= (0 , 2)
Thus, the y-axis, where x = 0, is equidistant from the two points.
Answer:
The y-axis is equidistant from both points
Step-by-step explanation:
we know that
The formula to calculate the coordinates of midpoint M between two points is equal to
\(M=(\frac{x1+x2}{2}, \frac{y1+y2}{2})\)
we have
\((x1,y1)=(-3,2)\)
\((x2,y2)=(3,2)\)
substitute the values in the formula
\(M=(\frac{-3+3}{2}, \frac{2+2}{2})\)
\(M=(0,2)\)
see the attached figure to better understand the problem
The y-axis is equidistant from both points