Answer:
The object’s resultant angle of motion with the +x-axis after the collision is 47 .
Step-by-step explanation:
It is given that Object A travels in the +x-direction before hitting a stationary object B. From object A’s x-momentum is \(5.7{\times}10^4kgms^{-1}\) and its y-momentum is \(6.2{\times}10^4kgms^{-1}\).
We know that tan of the angle from the x-axis is given as:
\(tanx=\frac{5.7{\times}10^4}{6.2{\times}10^4}\)
\(tanx=\frac{5.7}{6.2}\)
\(tanx=1.09\)
\(x=tan^{-1}(1.09)\)
\(x=47.4\)
Therefore, The object’s resultant angle of motion with the +x-axis after the collision is 47 .
