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Molly can prepare a report in 6 hours. Jere can prepare a report in only 4 hours.


Which of the following can be used to determine the amount of time it would take for Molly and Jere to prepare a report together?

Verified Answer :

Answer with explanation:

Time taken by Molly to prepare the Report = 6 hours

Work done in 1 hour \(=\frac{1}{6}\)

Time taken by Jere to prepare the Report = 4 hours

Work done in 1 hour \(=\frac{1}{4}\)

Their Combined Work , is given by the equation

          \(=\frac{1}{6}+\frac{1}{4}\\\\=\frac{6+4}{6\times 4}\\\\=\frac{10}{24}\)

Time it would take for Molly and Jere to prepare a report together is equal to

       \(=\frac{24}{10}\\\\=2.4\)

= 2.4 hours

             

Answer:

Total time taken by Molly and Jere to prepare a report together = 2.4 hours  

Step-by-step explanation:

Time taken by Molly to prepare a report = 6 hours

\(\text{So, one hour work of Molly = }\frac{1}{6}\text{ hours}\)

Time taken by Jere to prepare a report = 4 hours

\(\text{So, one hour work of Jere = }\frac{1}{4}\text{ hours}\)

Now, we need to calculate the total time taken by Molly and Jere to prepare a report together.

\(\text{Time taken by Molly and Jere to prepare a report together = }\frac{1}{6}+\frac{1}{4}\\\\\implies \frac{6+4}{24}\\\\\implies \frac{10}{24}\\\\\implies \text {Total time taken by Molly and Jere to prepare a report together = }\frac{24}{10} =2.4\text{ hours}\)

Hence, Total time taken by Molly and Jere to prepare a report together = 2.4 hours

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