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f(2)=2^2+2.2-1=4+4-1=7



f (-2)=(-2)^2+2. (-2)-1 =4-4-1= -1



f (3)=3^2+2.3-1=9+6-1=14



f (-3)=(-3)^2+2. (-3)-1=9-6-1=2

Answer:

The pair of coordinates of domain and range are (2,7),(-2,1),(3,14) and (-3,2).

Step-by-step explanation:

Domain is the set of inputs of x values and range is the set of outputs or f(x) values.

The given function is

\(f(x)=x^2+2x-1\)

Substitute x=2 in the given function,

\(f(2)=(2)^2+2(2)-1=7\)

The value of the function is 7 at x=2.

Substitute x=-2 in the given function,

\(f(-2)=(-2)^2+2(-2)-1=-1\)

The value of the function is -1 at x=-2.

Substitute x=3 in the given function,

\(f(3)=(3)^2+2(3)-1=14\)

The value of the function is 14 at x=3.

Substitute x=-3 in the given function,

\(f(-3)=(-3)^2+2(-3)-1=2\)

The value of the function is 2 at x=-3.

Therefore the pair of coordinates of domain and range are (2,7),(-2,1),(3,14) and (-3,2).

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