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Jake has proved that a function, f(x), is a geometric sequence. How did he prove that?


He showed that an explicit formula could be created.


He showed that a recursive formula could be created.


He showed that f(n) … f(n - 1) was a constant ratio.


He showed that f(n) - f(n - 1) was a constant difference.

Verified Answer :

The best and most correct answer among the choices provided by your question is the third choice or letter C.

Jake just proved that "that f(n) … f(n - 1) was a constant ratio."

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scme1702

The characteristic of a geometric progression is that the ratio of a term and its consecutive term remains the same. Thus, if he can show that f(n)/f(n-1) remains constant, he can prove f(x) to be a geometric progression.
The third option is correct.

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