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Given the geometric sequence where a1 = 4 and the common ratio is 3, what is the domain for n?


All integers where n ≥ 1


All integers where > 1


All integers where n ≥ 4


All real numbers

For this its always greater than one right? for every type of these things?



also Given the arithmetic sequence an = 4 − 3(n − 1), what is the domain for n?


All integers where n ≥ 1


All integers where n > 1


All integers where n ≤ 4


All integers where n ≥ 4

Verified Answer :

syed514

Since r is greater than 1, that means integers greater than or equal to 1.
It can't be all real numbers, because that would include negative number.

If the starting number of a sequence is 4, if we put n=0, then we get 4, but if we put in a negative n, we would get a value that isn't part of our sequence, so it has to be n is greater than or equal to 1.

Answer:

All integers where n ≥ 1

Step-by-step explanation:

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