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Simplify and select the answer with the appropriate restrictions for the variables.


10x^2-15x/5x^2



A.2-15x,(x_0)





B.2-3x,(x_0)





C.2x-3/x,(x_0)





D.10x-3,(x_0)

Verified Answer :

JcAlmighty

The answer is C.2x-3/x,(x_0)

\(\frac{10 x^{2} -15x}{5 x^{2} } = \frac{2x*5x -3*5x}{5 x^{2} }= \frac{5x(2x-3)}{5x*x}\)
5x can be canceled out, thus:
\(\frac{5x(2x-3)}{5x*x} = \frac{2x-3}{x}\)
Since x is denominator and if denominator is 0, the terms would be undefined, then x≠ 0

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