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A ball is thrown into the air with an upward velocity of 36 ft/s. Its height h in feet after t seconds is given by the function

h=-16t^2+36t+10 In how many seconds does the ball reach its maximum height? Round to the nearest hundredth if necessary. What is the ballÍs maximum height?

Verified Answer :

HomertheGenius

h = - 16 t² + 36 t + 10
The maximum height of the ball is at the vertex of the parabola.
t = - b / 2 a
t = -36/-32
t = 1.12 s
The maximum height of the ball:
h max = - 16 1.12² + 32 1.12 + 10 = - 16 * 1.2544 + 35.84 + 10 =
=  - 20.0704 + 45.84 = 25.7696 = 25.77 m

josiahcat5980

Answer:

25.77 m

Step-by-step explanation:

The maximum height of the ball:

h max = - 16 1.12² + 32 1.12 + 10 = - 16 * 1.2544 + 35.84 + 10 =  

=  - 20.0704 + 45.84 = 25.7696 = 25.77 m

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