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In a closed system, Glider A with a mass of 0.40 kg and a speed of 4.00 m/s collides with Glider B at rest with a mass of 0.40 kg. The two interlock and move off. What speed are they moving?


0.50 m/s


1.0 m/s


2.0 m/s


4.0 m/s

Verified Answer :

This is an example of a perfect inelastic collision. After the collision the two gliders move as one object. Since the system is closed, total momentum is conserved. 
P1 = P2P1 = PA1 + PB1, PA1 - momentum of glider A before collision                PB1 - momentum of glider B before collisionP1 = (0.40)(4.00) + (0.40)(0.00) = 1.60 kg-m/sP2 = (0.40 + 0.40)(v), v is the final velocity of the two objects1.60 = 0.80v
Therefore, v = 2.00 m/s


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