Verified Answer :
Answer:The pH of the solution -0.60 .The pH scales ranges value from 1 to 14.So, the given pH of the solution is coming out to negative which means that in a lab preparation of solution with this pH is not feasible.
Explanation:
The pH of the solution defined as negative logarithm of \([H^+]\) ion concentration.
\(H_2SO_4(aq)\rightarrow 2H^+(aq)+SO_4^{2-}(aq)\)
According to reaction 1 moles of sulfuric acid gives 2 moles of \(H^+\)
Then 2 mol /L solution of sulfuric acid will give = 4 mol/L of \(H^+\) ions.
\(pH=-\log[H^+]=-\log[4.0]=-0.60\)
The pH scales ranges value from 1 to 14.So, the given pH of the solution is coming out to negative which means that in a lab preparation of solution with this pH is not feasible.
-0.6 is the calculated value of pH which is not possible because pH ranges from 1 to 14.
How we calculate the pH?
pH is define as the negative logarithm of the concentration of H⁺ ions and represented as:
pH = -log [H⁺]
Chemical equation for sulfuric acid is written as:
H₂SO₄ → 2H⁺ + SO₄²⁻
From the stoichiometry of above equation it is clear that 1 mole of H₂SO₄ will produce 2 mole of H⁺ ions. So, 2 moles of H₂SO₄ will produce 4 mole of H⁺ ions and equation of pH becomes:
pH = -log (4)
pH = -0.6.
But we know that pH scale ranges from 1 to 14, so given value of concentration is wrong.
Hence, calculated value of pH is -0.6.
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