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Help with horizontal distance, initial velocity and angles problem?

  1. Recall that the equation for the horizontal distance h in feet of a projectile with initial velocity v0 and initial angle theta is given by h=v0^2/16 sin theta cos theta.



AAssume the initial velocity is 60 feet/second . What initial angle will you need to ensure that the horizontal distance will be exactly 100 feet?

BAssume the initial velocity is 60 feet/second. What is the maximum horizontal distance possible and at what angle does this occur?

Verified Answer :

The solution to your problem is as follows:

1600 = 60^2*sintcost = 3600sintcost = 1800sin2t 
2t = 62.73 
t = 31.37 degrees

The other would be 90 - 31.37 = 58.63 degrees

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

syed514

The solution to your problem is as follows:

1600 = 60^2*sintcost = 3600sintcost = 1800sin2t 
2t = 62.73 
t = 31.37 degrees

The other would be 90 - 31.37 = 58.63 degrees

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

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