a line segment has (x1,y1) as one endpoint and (xm,ym) as its midpoint. Find the other endpoint (x2,y2)of the line segment in terms of x1,y1,xm, and ym.
A line segment has (x1, y1)as one endpoint and (xm, ym)as its midpoint.
Use the formula? (x2, y2) = (2xm − x1, 2ym − y1)
to find the coordinates of the endpoint of a line segment if the coordinates of the other endpoint and midpoint are (1, 8), (−3, −1) and (−7, 16), (3, 6),respectively.
(a) Endpoint: (1, 8), (−3, −1)
(x2, y2) = ( , )
(b) Midpoint: (−7, 16), (3, 6)
(x2, y2) = ( , )
ANSWER
= {(2(-3)-1), (2(-1)-8)}
= (-7,-10)
Answer b) (x2,y2) = (2x-x1, 2y-y1) for midpoints m = 1
= {(2(3)+7), (2(6)+16)}
= (13,28)
(x1,y1)
(x2,y2)
(xm,ym)
Midpoint formula is given as below.
((x1 + x2)/2 , (y1 + y2)/2 )
Where
(x1 + x2)/2 = xm ----------- (1)
(y1 + y2)/2 = ym ----------- (2)
Equation (1) implies that;
x1 + x2 = 2xm
x2 = 2xm – x1
Equation (2) implies that;
y1 + y2 = 2ym
y2 = 2ym – y1
Thus the end point is
(x2,y2) = (2xm – x1, 2ym – y1)