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A juggler is performing her act using several balls. She throws the balls up at an initial height of 4 feet, with a speed of 15 feet per second. If the juggler doesn't catch one of the balls, about how long does it take the ball to hit the floor?


Hint: Use H(t) = _16t2 + vt + s.


7.52 seconds

1.15 seconds

0.47 second

0.22 second

Verified Answer :

The correct
answer between all the choices given is the second choice, which is 1.15 seconds. I am
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Answer:

The ball will take 1.15 seconds to hit the floor.

Explanation:

It is given that,

A juggler is performing her act using several balls. The height as a function of time is given by :

\(h(t)=-16t^2+vt+s\).............(1)

where

v is the speed of the ball

s is initial height

t is time taken

Putting h(t) = 0 and solving equation (1)

\(-16t^2+vt+s=0\)

\(-16t^2+15t+4=0\)

On solving above equation using graphing calculator and solving for t we get, t = 1.154 seconds

Hence, the correct option is (b) " 1.15 seconds ".

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