how many moles are in 1.2x10^3 grams of ammonia(NH3) ?
Molar mass NH3 = 17.031 g/mol
1 mole NH3 ---------- 17.031 g
?? moles -------------- 1.2x10³ g
moles NH3 = 1 x ( 1.2x10³ ) / 17.031
moles NH3 = 1.2x10³ / 17.031
= 70.45 moles of NH3
hope this helps!
Answer : The number of moles present in ammonia is, 70.459 moles.
Solution : Given,
Mass of ammonia = \(1.2\times 10^3g\)
Molar mass of ammonia = 17.031 g/mole
Formula used :
\(\text{Moles of }NH_3=\frac{\text{ given mass of }NH_3}{\text{ molar mass of }NH_3}\)
\(\text{Moles of }NH_3=\frac{1.2\times 10^3g}{17.031g/mole}=70.459moles\)
Therefore, the number of moles present in ammonia is, 70.459 moles.