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WallyJ
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A given line has the equation 2x + 12y = −1.


What is the equation, in slope-intercept form, of the line that is perpendicular to the given line and passes through the point (0, 9)?


y = ( ? )x + 9



what is the question mark?

Verified Answer :

Azieq

2x + 12y = - 1
12y = - 2x - 1
y = - x/6 - 1/12

m1 = - 1/6
m1 × m2 = - 1
- 1/6 × m2 = - 1
m2 = 6

y = 6x + c , ( 0,9 )
9 = 6( 0 ) + c
c = 9
y = 6x + 9

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lhmarianateixeira

The equation of the second line can be write as y = 6x + 9.

How to calculate the equation of a line?

The line has two possible equations, the general equation of the line and the reduced equation of the line. The reduced equation of the line is y = mx + n, where x and y are, respectively, the independent variable and the dependent variable; m is the slope, and n is the linear coefficient.

The slope-intercept form of a linear equation is:

\(y = mx +c\)

Where:

  • m = slope
  • c =  intercept

In this case we have:

\(2x + 12y = -1\\12y = -2x -1\\y = -1/6y -1/12\)

The line that is perpendicular to this line will have:

\(m_1 = - 1/6\\m_1 * m_2 = - 1\\- 1/6 * m_2 = - 1\\m_2 = 6\)

Equation of the second line:

\(y = 6x + c , ( 0,9 )\\9 = 6( 0 ) + c\\c = 9\\y = 6x + 9\)

See more about  slope-intercept at brainly.com/question/12763756

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