Answer:
The coordinates of image are A'(-2,1), B'(1,0) and C'(-1,0).
Step-by-step explanation:
From the figure it is clear that the coordinates of triangle are A(0,0), B(1,3) and C(1,1).
∆ABC is translated 2 units down and 1 unit to the left.
\((x,y)\rightarrow (x-1,y-2)\)
\(A(0,0)\rightarrow (0-1,0-2)=(-1,-2)\)
\(B(1,3)\rightarrow (1-1,3-2)=(0,1)\)
\(C(1,1)\rightarrow (1-1,1-2)=(0,-1)\)
Then it is rotated 90° clockwise about the origin to form ∆A′B′C′.
\((x,y)\rightarrow (y,-x)\)
\((-1,-2)\rightarrow A'(-2,1)\)
\((0,1)\rightarrow B'(1,0)\)
\((0,-1)\rightarrow C'(-1,0)\)
Therefore the coordinates of image are A'(-2,1), B'(1,0) and C'(-1,0).
