To find your x-intercepts, set f(x)=0, so 0=x^6-63x^3-64. You can do this by factoring x^6-63x^3-64 into \((x^3-64)(x^3+1)\), giving you \((x^3-64)(x^3+1)=0\). Next, solve each factor for x if f(x)=0, so \((x^3-64)=0\) and \((x^3+1)=0\). Solving for x gives you \(x= \sqrt[3]{64} =4\) and \(x= \sqrt[3]{-1}=-1\), meaning your x-intercepts are (4,0) and (-1,0)
