Given a triangle with a =14 A = 41 and B = 34, what is the length of c? Round to the nearest tenth
Answer:
20.6°
Step-by-step explanation:
Given in a triangle
a = 14 ∠A = 41° and ∠B = 34°
Then we have to find the measure of side c
Since sum of all angles of a triangle is 180°
So ∠A + ∠B + ∠C = 180°
41° + 34° + ∠C = 180°
75° + ∠C = 180°
∠C = 180 - 75
= 105°
Now from sine rule,
\(\frac{a}{SinA}= \frac{c}{SinC}\)
\(\frac{14}{Sin(41)}= \frac{c}{Sin(105)}\)
\(c=\frac{14\times Sin(105)}{Sin(41)}\)
\(c=\frac{14\times 0.9659}{0.6561}\)
= 20.61°
≈ 20.6°