Answer:
Part 1) The length of the terrace is \(15\ ft\)
Part 2) The width of the terrace is \(6\ ft\)
Part 3) The area of the terrace is \(90\ ft^{2}\)
Step-by-step explanation:
we know that
The scale of the plan is \(\frac{2}{6} \frac{in}{ft}\)
see the attached figure to better understand the problem
Step 1
Find the length of the terrace
we know that
The length of a terrace in the plan is equal to \(5\ in\)
so
by proportion
Find the length of the terrace in the actual
\(\frac{2}{6} \frac{in}{ft}=\frac{5}{x} \frac{in}{ft}\\ \\x=6*5/2\\ \\x=15\ ft\)
Step 2
Find the width of the terrace
we know that
The width of a terrace in the plan is equal to \(2\ in\)
so
by proportion
Find the width of the terrace in the actual
\(\frac{2}{6} \frac{in}{ft}=\frac{2}{x} \frac{in}{ft}\\ \\x=6*2/2\\ \\x=6\ ft\)
Step 3
Find the area of a terrace
we know that
The area of a terrace is equal to
\(A=LW\)
we have
\(L=15\ ft\)
\(W=6\ ft\)
substitute
\(A=15*6=90\ ft^{2}\)
