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jwhite17
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A theater company with 9 actors is putting on a play that has 3 roles. In how many different ways can the director assign actors to those roles?

Verified Answer :

He has 9 choices for the first role, and that leaves him 8 people to choose for the second so he has 98 = 72 choices for the first two roles; that leaves 7 possible choices for the third role so that gives him 98*7 choices or 504 different ways he can assign the roles. i think this is correct. 







trascaandrei

9!/(3!6!)=78*9/6=84

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