Answer:
range is y≥0
C is correct option.
Step-by-step explanation:
The given equation is \(y=x^2\)
Range is the set of y values for which the function is defined.
Hence, we solve the equation for x and then check for which y values the function is defined.
take square root both sides
\(\pm\sqrt{y}=\sqrt{x^2}\\\\x=\pm\sqrt{y}\)
Now, square root function is defined for positive values only.
Hence, for the above function to be defined, y≥0
Hence, range is y≥0
C is correct option.
