If a ping pong ball falls from the top of a building that is 168 feet high , how many seconds will it take the ball to hit the ground ? The formula for distance is d=16t^2
here given 'd' that is distance is 168 feet. we need to find seconds that is 't'. from the given formula, ⇒ d=16 t² ⇒ \(\frac{d}{16}\) = t² ⇒ t²= \(\frac{168}{16}\) ⇒ t²= 10.5 ⇒ t=\(\sqrt{10.5}\) ⇒ t=3.24 thus the seconds required is 3.24 seconds
