we know that
The formula to calculate the solutions of the quadratic equation of the form \(ax^{2} +bx+c=0\) is equal to
\(x=\frac{-b(+/-)\sqrt{b^{2}-4ac}}{2a}\)
in this problem we have
\(h^{2} +5h=295\)
equate to zero
\(h^{2} +5h-295=0\)
\(a=1\ b=5\ c=-295\)
substitute in the formula
\(x=\frac{-5(+/-)\sqrt{5^{2}-4(1)(-295)}}{2*1}\)
\(x=\frac{-5(+/-)\sqrt{25+1,180}}{2}\)
\(x=\frac{-5(+/-)\sqrt{1,205}}{2}\)
the positive solution is
\(x=\frac{-5+\sqrt{1,205}}{2}=14.86\ yd\)
therefore
the answer is
The height is \(14.86\ yd\)
