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Verified Answer :

5x^2+3x-4=0 
x^2+3x/5-4/5=0 
x^2+3x/5=4/5 
x^2+3x/5+9/100=89/100 
(x+3/10)^2=89/100 
x+3/10=±(√89)/10 
x=-3/10±√89/100 
x=-3±(√89/10)

Answer:

The equation \(x=\frac{-3\pm \sqrt{(3)^2-4(5)(-4)}}{2(5)}\) shows the quadratic formula used correctly to solve the given quadratic equation.

Step-by-step explanation:

The given equation is

\(5x^2+3x-4=0\)            .... (1)

If a quadratic equation is defined as

\(ax^2+bx+c=0\)           ..... (2)

then the quadratic formula is

\(x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\)

From equation (1) and (2), we get

\(a=5,b=3,c=-4\)

Using quadratic formula we get

\(x=\frac{-3\pm \sqrt{(3)^2-4(5)(-4)}}{2(5)}\)

Therefore the equation \(x=\frac{-3\pm \sqrt{(3)^2-4(5)(-4)}}{2(5)}\) shows the quadratic formula used correctly to solve the given quadratic equation.