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Verified Answer :

MissPhiladelphia

Given that y =c(x)=^3√x . solving for the value of y for x =
0, 0.008, 0.027, 0.064, 0.125, 0.216, 0.343, 0.512, 0.729, and 1. The value of
y with its corresponding x are:

X             y

0              0

0.008     0.2

0.027     0.3

0.064     0.4

0.125     0.5

0.216     0.6

0.343     0.7

0.512     0.8

0.729     0.9

1              1

Step-by-step explanation:

We are given a function as:

\(y=c(x)=\sqrt[3]{x}\)

We have to find the value of the function at different values of x:

1)

when x=0

\(y=\sqrt[3]{0}\\\\y=0\)

Hence, y=0

2)

when x=0.008

\(y=\sqrt[3]{0.008}\\\\y=\sqrt[3]{(0.2)^3}\\\\y=0.2\)

Hence y=0.2

3)

when x=0.027

\(y=\sqrt[3]{0.027}\\\\y=\sqrt[3]{(0.3)^3}\\\\y=0.3\)

Hence, y=0.3

4)

when x=0.064

\(y=\sqrt[3]{0.064}\\\\y=\sqrt[3]{(0.4)^3}\\\\y=0.4\)

Hence, y=0.4

5)

when x=0.125

\(y=\sqrt[3]{0.125}\\\\y=\sqrt[3]{(0.5)^3}\\\\y=0.5\)

Hence, y=0.5

6)

when x=0.216

\(y=\sqrt[3]{0.216}\\\\y=\sqrt[3]{(0.6)^3}\\\\y=0.6\)

Hence, y=0.6

7)

when x=0.343

\(y=\sqrt[3]{0.343}\\\\y=\sqrt[3]{(0.7)^3}\\\\y=0.7\)

Hence, y=0.7

8)

when x=0.512

\(y=\sqrt[3]{0.512}\\\\y=\sqrt[3]{(0.8)^3}\\\\y=0.8\)

Hence, y=0.8

9)

when x=0.729

\(y=\sqrt[3]{0.729}\\\\y=\sqrt[3]{(0.9)^3}\\\\y=0.9\)

Hence, y=0.9

10)

when x=1

\(y=\sqrt[3]{1}\\\\y=\sqrt[3]{(1)^3}\\\\y=1\)

Hence, y=1

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