we know that
Based on the FIFA rules for international matches, dimensions of fields are: Length: minimum \(100\) m, maximum \(110\) m. Width: minimum \(64\) m, maximum \(75\) m.
we know that
The area of a rectangle is
\(A=L*W\)
where
L is the length side of the field
W is the width side of the field
In this problem we have
\(W=75\ yd\\A=7500\ yd^{2}\)
Step \(1\)
Find the value of L
\(A=L*W\)
\(L=A/W\)
substitute the values
\(L=7500/75=100\ yd\)
Step \(2\)
Convert yards to meters
we know that
\(1 \ yard =0.9144\ meters\)
\(L=100\ yard=100*0.9144=91.44\ meters\)
\(W=75\ yard=75*0.9144=68.58\ meters\)
Step \(3\)
Compare the dimensions of the field with the dimensions of FIFA regulation
Length: minimum \(100\) m, maximum \(110\) m
Length of the field=\(91.44\ meters\)
The length does not satisfy the measures of the FIFA regulation
because
\(91.44\ meters < 100\ meters\)
therefore
the answer is
The field does not satisfy the measures of the FIFA regulation
