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(05.02)A doghouse is to be built in the shape of a right trapezoid, as shown below. What is the area of the doghouse?


A right trapezoid with top side 7 feet and height 7 feet. The bottom side is extended to the right with 3 more feet.

24.5 square feet

59.5 square feet

70 square feet

147 square feet

Verified Answer :

The answer is 59.5 square feet. To solve this, you need to know the formula for the area of a trapezoid, which is: A= h(b1+b2/2). This means that the Area is equal to the height multiplied by base 1 + base 2 divided by 2. So the equation would look like this:

A= 7(7+10)
    -------------
           2

A= 7(17)
    -----------
         2
A= 119
    ----------
        2
A= 59.5 square feet

Answer:

The area of the doghouse is \(59.5\ ft^{2}\)

Step-by-step explanation:

we know that

The area of trapezoid is equal to

\(A=\frac{1}{2}(b1+b2)h\)

where

b1,b2 are the parallel bases of trapezoid

h is the height of trapezoid

in this problem we have

\(b1=7\ ft\)

\(b2=7+3=10\ ft\)

\(h=7\ ft\)

substitute

\(A=\frac{1}{2}(7+10)7=59.5\ ft^{2}\)