So we want to solve 2x − 40 = 3y for x2x − 40 + 40 = 3y + 40(Add 40 to both sides!)2x = 3y + 40
Now divide both sides by 2!
\(\frac{2x}{2} = \frac{3y + 40}{2} \ \textgreater \ x = \frac{3}{2}y + 20\)
Now substitute \(\frac{3}{2}y + 20 for x in 2y = -4x + 48\)
\(2y = -4( \frac{3}{2}y + 20) + 48\)
Which then gives us..
2y = −6y − 32(Make sure to simplify both sides of the equation)2y + 6y = −6y − 32 + 6y(Now add 6y to both sides)8y = −32
Now divide both sides by 8
\(\frac{8y}{8} = \frac{-32}{8} \ \textgreater \ y = -4\)
Now we have to substitute -4 for y in \(x = \frac{3}{2}y + 20 \ \textgreater \ \frac{3}{2}(-4) + 20 \ \textgreater \ x = 14\)
So we end up getting...
x = 14 and y = −4.
Hope this helps!
