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Verified Answer :

syed514

Elastic energy (E1) stored in the spring when it is stretched by x : 
=1/2kx^2=1.5J 

when it is stretched 3 times more=>x becomes 3x 
so
E2=1/2k(3x)^2 
=1/2k{9x^2} 
=9{1/2kx^2} 
={(E1}
=9{1.5} 
=13.5J
hope it helps

Lanuel

The quantity of energy that would be stored in this spring is given by \(U=\frac{1}{2} k(3x)^2\)

How to calculate the energy stored.

Mathematically, the energy stored in a spring is given by this formula:

\(U=\frac{1}{2} kx^2\)

Where:

  • k is the force constant.
  • U is the energy.
  • x is the extension.

In this scenario, the spring was stretched three (3) times as far. Thus, its extension is equal to three (3).

Substituting the given parameters into the formula, we have;

\(U=\frac{1}{2} k(3x)^2\)

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