Answer:
The average speed for the record time is 9.78 m/s.
Explanation:
Given that,
Total distance \(d= 2.00\times10^2\ km\)
Time \(t= 5\times60\times60+40\times60+37\ sec\)
\(t =20437\ sec\)
We need to calculate the average speed for the record time
Using formula of the average speed
\(v_{avg}=\dfrac{D}{T}\)
Where, D = total distance
T = total time
Put the value into the formula
\(v_{avg}=\dfrac{2.00\times10^2\times10^{3}}{20437}\)
\(v_{avg}=9.78\ m/s\)
Hence, The average speed for the record time is 9.78 m/s.
