Verified Answer :
Answer:
The width of the spacing between each board is \(\frac{21}{56}\) inches.
Step-by-step explanation:
Given: Each board \(9\frac{1}{4} inches\).
Let's convert the mixed number \(9\frac{1}{4} inches\) to improper fraction.
\(9\frac{1}{4} = \frac{37}{4}\)
Total width of 15 boards = \(15 . \frac{37}{4} = 138 \frac{3}{4}\) inches
Now we have to find the total space between the boards.
The total space = 144 - \(138 \frac{3}{4}\)
The total space = \(5 \frac{1}{4}\)
There 14 equal spaces between each board.
To find the width of spacing between each board, we need to divide \(5 \frac{1}{4}\) by 14.
The width of spacing between each board = \(\frac{5\frac{1}{4} }{14}\)
Now we can convert the mixed number to improper and multiply with the reciprocal of 14.
The reciprocal of 14 is \(\frac{1}{14}\)
= \(\frac{21}{4} . \frac{1}{14} = \frac{21}{56}\)
Therefore, the width of the spacing between each board is \(\frac{21}{56}\) inches.
The spacing inbetween successive boards can be obtained using arithmetic expression. Hence, the between the boards is \(\frac{3}{8}\)
- Width of each board = \(9 \frac{1}{4} inches\)
- Number of boards = 15 Boards
- Total width of the section = 144 inches
- Number of spaces = 14
Let the size per spacing = n
We could write the expression thus :
- \((\frac{37}{4} \times 15) + 14n = 144\)
\((\frac{555}{4}) + 14n = 144\)
\(14n = 144 - \frac{555}{4}\)
\(14n = \frac{576 - 555}{4} = \frac{21}{4}\)
\(14n= \frac{21}{4}\)
\(14n \times 4 = 21\)
\(n = \frac{21}{56} = \frac{3}{8} inches\)
Therefore, the spacing inbetween successive boards is \(\frac{3}{8}\)
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