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Find three consecutive integers whose sum is 9 greater than twice the largest integer

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texaschic101

ur 3 consecutive integers : x, x + 1, x + 2

x + x + 1 + x + 2 = 2(x + 2) + 9
3x + 3 = 2x + 4 + 9
3x + 3 = 2x + 13
3x - 2x = 13 - 3
x = 10

x + 1 = 10 + 1 = 11
x + 2 = 10 + 2 = 12

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