Answer:
The roots of the given quadratic function \(f(b) = b^2-75\) is \(5\sqrt{3}\quad\) and \(-5\sqrt{3}\quad\)
Step-by-step explanation:
Given: Quadratic function \(f(b) = b^2-75\)
We have to find the roots of the given quadratic function \(f(b) = b^2-75\)
Since, roots of the quadratic equation is the points where the value of function is zero.
That is f(x) = 0
Consider the given function \(f(b) = b^2-75\)
Put f(b) = 0
\(\Rightarrow b^2-75=0\)
Simplify , we have,
\(\Rightarrow b^2=75\)
Taking square root both side, we have,
\(\Rightarrow b=\sqrt{75}\)
Simplify we have,
\(\Rightarrow b=\pm 5\sqrt{3}\quad\)
Thus, The roots of the given quadratic function \(f(b) = b^2-75\) is \(5\sqrt{3}\quad\) and \(-5\sqrt{3}\quad\)
