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What is an equation of a line, in point-slope form, that passes through (1, −7) and has a slope of −2/3 ?

Ay+7=−23(x−1)y+7=−23(x−1)

By−7=23(x−1)y−7=23(x−1)

Cy−7=−23(x+1)y−7=−23(x+1)

Dy+7=23(x+1)y+7=23(x+1)

Verified Answer :

sid17

y-y1=m(x-x1)

substitute

y+7=-2/3(x-1)
y+7=2/3(-x+1)
or
y+7=-2/3x +2/3


i have no idea what those options are for but the most likely answer looks like option A

JeanaShupp

Answer:- A. \(y+7=\frac{-2}{3}(x-1)\)


Explanation:-

We know that the equation of a line passing through point (a,b) whose slope is m, is

\((y-b)=m(x-a)\)

Thus, the equation of a line passing through point (1, −7) whose slope \(\frac{-2}{3}\) is ,

\((y-(-7))=\frac{-2}{3}(x-1)\)

\(\\\Rightarrow(y+7)=\frac{-2}{3}(x-1)\)

∴ A. is the right answer. The equation of a line passing through point (1, −7) whose slope \(\frac{-2}{3}\) is \((y+7)=\frac{-2}{3}(x-1)\).

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