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Boyle's law balloon was filled to a volume of 2.50 l when the temperature was 30.0∘

Cwhat would the volume become if the temperature dropped to 11.0∘

c.

Verified Answer :

taskmasters

To solve this we assume
that the gas inside the balloon is an ideal gas. Then, we can use the ideal gas
equation which is expressed as PV = nRT. At a constant pressure and number of
moles of the gas the ratio T/V is equal to some constant. At another set of
condition of temperature, the constant is still the same. Calculations are as
follows:

T1 / V1 = T2 / V2

V2 = T2 x V1 / T1

V2 =284.15 x 2.50 / 303.15

V2 = 2.34 L

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