Diane serves breakfast to two groups of children at a daycare center . One box of Oates contain 12 cups of cereal . She needs 1/3 cup for each younger child and 3/4 cup for each older child . Today group includes 11 younger children and 10 older children . Is one box of parties enough for everyone?
We have 11 younger children, and we need 1/3 cups for each. So we need 11/3 cups for the younger children. We have 10 older children, and we need 3/4 cups for each. So we need 30/4 cups for the older children. 30/4+11/3 is the total number. But now we have to find a common denominator. Our common denominator in this instance is 12, so we just apply that. 90/12+44/12. 90+44=134/12=11.166667. So the answer is yes, one box is enough. Hope this helps!
Answer:
Yes, one box of parties is enough for everyone.
Step-by-step explanation:
Given,
Cereal contained by one box = 12 cups,
Also, each young child needs cereal = \(\frac{1}{3}\) cup,
So, the cups needed for 11 younger child = \(\frac{11}{3}\) cups
Also, each older child needs cereal = \(\frac{3}{4}\) cup,
So, the cups needed for 10 older children = \(\frac{30}{4}\) cups,
Thus, the total cups needed = \(\frac{11}{3}+\frac{30}{4}\)
\(=\frac{44+90}{12}\)
\(=\frac{134}{12}\)
\(=11\frac{1}{6}\)
\(\because 11\frac{1}{6} < 12\)
Hence, one box of parties is enough for everyone.