Answer:
The value of f(1)=31
Step-by-step explanation:
Given: \(f(n+1)=f(n)-3\)
f(4)=22
We need to find the f(1)
Put n=3 into recursion formula
\(f(3+1)=f(3)-3\)
\(f(3)=22+3=25\)
Put n=2 into recursion formula
\(f(2+1)=f(2)-3\)
\(f(2)=25+3=28\)
Put n=1 into recursion formula
\(f(1+1)=f(1)-3\)
\(f(1)=28+3=31\)
Hence, The value of f(1)=31
