Answer:
Option C. 1/221
Step-by-step explanation:
Total cards in a standard deck of cards = 52
Number of ace in a deck of cards = 4
So probability to draw an ace \(P_{1}=\frac{4}{52}\)
Since the cards were drawn without replacement means remaining cards in deck of cards now = 51
Number of aces remaining = 3
So probability of drawing another ace \(P_{2}=\frac{3}{51}\)
Now probability to draw both the aces
= \(P_{1}\times P_{2}\)
\(\frac{4}{52}\times \frac{3}{51}=\frac{1}{13}\times \frac{1}{17}\)
= \(\frac{1}{221}\)
Option C. is the answer.
