The solution of the inequality \(3 + 7x < 26\) is \(\boxed{x < \frac{{23}}{7}}{\text{ or }}\boxed{x = 3\frac{2}{7}}.\)
Further explanation:
The solutions of the linear inequality lie in the intervals.
If the linear equality is \(x < a\), than the solutions of the inequality lies in the interval of \(\boxed{\left( { - \infty ,a} \right)}.\)
Given:
The statement is 3 more than the product of 7 and a number x is less than 26.
Explanation:
The inequality from the statement can be obtained as follows,
\(3 + 7x < 26\)
Solve the above inequality to obtained solution.
\(\begin{aligned}3 + 7x &< 26\\3 + 7x - 3 &< 26 - 3\\7x &< 23\\\frac{{7x}}{7} &< \frac{{23}}{7}\\x &< \frac{{23}}{7}\\x&< 3\frac{2}{7}\\\end{aligned}\)
The solution of the inequality \(3 + 7x < 26\) is \(\boxed{x < \frac{{23}}{7}}{\text{ or }}\boxed{x = 3\frac{2}{7}}.\)
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Answer details:
Grade: High School
Subject: Mathematics
Chapter: Linear inequality
Keywords: inequality, statement, product, 3, more, number, less than, solution, solution set, fraction, integer, x.
