Answer:
There is no quadratic equation which has solution x = 1 or -5
Step-by-step explanation:
For part A)
\(x^{2}+2x+4\)
\(\mathrm{Could\:not\:factor\:further}\)
\(\mathrm{Factor}\:0\)
For part B)
\(x^{2}-2x+4\)
\(\mathrm{Could\:not\:factor\:further}\)
\(\mathrm{Factor}\:0\)
For part C)
\(x^{2}+2x-4\)
\(\mathrm{Could\:not\:factor\:further}\)
\(\mathrm{Factor}\:0\)
For part D)
\(x^{2}+2x-4\)
\(\mathrm{Could\:not\:factor\:further}\)
\(\mathrm{Factor}\:0\)
There is no quadratic equation which has solution x = 1 or -5
