Answer:
Net displacement, d = 44.72 meters
Explanation:
In the attached figure, OA shows the net displacement.
Distance 1, d₁ = 30 m
Distance 2, d₂ = 40 m
Distance 3, d₃ = 50 m
Displacement of an object is equal to the shortest distance covered by an object. Here, the net displacement of the person can be calculated as :
\(d=\sqrt{(50-30)^2+40^2}\)
d = 44.72 meters
So, the net displacement of the boy is 44.72 meters. Hence, this is the required solution.
