Answer:
\(I^{-}\)
\(K^{+}\)
Explanation:
As iodine has a higher electronegativity value and 7 valence electrons, it takes the valence electron of potassium to complete 8 electrons in its valence shell thus forming the anion \(I^{-}\) and, as consequence of losing one electron, the K atoms forms the cation \(K^{+}\)
The formula of potassium iodide is KI
