we have
\(x^{2}-8x=3\)
Complete the square. Remember to balance the equation by adding the same constants to each side
\(x^{2}-8x+16=3+16\)
\(x^{2}-8x+16=19\)
Rewrite as perfect squares
\((x-4)^{2}=19\)
\((x-4)^{2}=19\\ (x-4)=(+/-)\sqrt{19} \\ \\ x1=4+\sqrt{19} =8.359\\ x2=4-\sqrt{19} =-0.359\)
therefore
the answer is
\(x1=4+\sqrt{19} =8.359\\x2=4-\sqrt{19} =-0.359\)
