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A cat chases a mouse across a 1.2 m high table. The mouse steps out of the way, and the cat slides off the table and strikes the floor 1.3 m from the edge of the table.

What was the cat’s speed when it slid off the table? The acceleration of gravity is 9.81 m/s2 .

Answer in units of m/s.

Verified Answer :

jaelynneterry

i think it is 7.5 m/s but im not entirely sure

onyebuchinnaji

Answer:

2.63 m/s

Explanation:

Step 1: identify the given parameters

height, H = 1.2 m

horizontal distance, d = 1.3 m

initial velocity, u = 0 m/s

acceleration due to gravity, = 9.81 m/s²

time, t = ?

the cat's speed, v = ?

Step 2: calculate the time it took the cat to reach a height of 1.2 m

\(H = ut +\frac{1}{2}gt^2\)

Since u = 0, the equation reduces to;

\(H =\frac{1}{2}gt^2\), re-arrange this equation to obtain 't'

\(t = \sqrt{\frac{2h}{g}} \\\)

\(t = \sqrt{\frac{2*1.2}{9.81}} \\\)

t = 0.495 s

Step 3: calculate the speed it took the cat to reach horizontal distance of 1.3m

d = v*t

v = d/t

v = 1.3/0.495

v = 2.63 m/s

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