I need to solve cy−7=5d+3y for y, any help?
Given cy - 7 = 5d + 3y, we solve for y as follows:
cy - 3y = 5d + 7
y(c - 3) = 5d + 7
y = (5d + 7) / (c - 3)
For this case we have the following equation:
\(cy-7 = 5d + 3y
\)
We must clear the value of y.
For this, we follow the following steps:
1) We place the variables on one side of the equation and the constant terms on the other side of the equation:
\(cy-3y = 5d + 7
\)
2) We make the common factor "y" on the left side of the equation:
\(y(c-3) = 5d + 7
\)
3) We move to divide c-3 on the right side of the equation:
\(y = \frac{5d + 7 }{c-3}\)
Answer:
The value of y is given by:
\(y = \frac{5d + 7 }{c-3}\)