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Verified Answer :

ModNov

3(8 – 4x) < 6(x – 5)?- 12x + 24 < 6x - 30
- 12x - 6x < - 30 - 24
- 18x < - 54 .(- 1)
  18x > 54
      x > 54/18
      x > 3

we have

\(3(8-4x)<6(x-5)\)

Eliminate the parenthesis

\(24-12x<6x-30\)

Group terms that contain the same variable, and move the constants to the opposite side of the inequality

\(24+30<6x+12x\)

\(54<18x\)

Divide by \(18\) both sides

\(54/18

\(3

rewrite the inequality

\(x>3\)

the solution is the interval-------> (3,∞)

The answer in the attached figure

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