Answer:
The answer is
the value of the leading coefficient is equal to \(1\)
Step-by-step explanation:
we know that
The formula to solve a quadratic equation of the form \(ax^{2} +bx+c=0\) is equal to
\(x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}\)
in this problem we have
\(f(x)=x^{2} -8x-4\)
equate the function to zero
\(x^{2} -8x-4=0\)
so
\(a=1\\b=-8\\c=-4\)
the value of the leading coefficient is equal to a
\(a=1\)
